10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    The value of cos \[(-\text{ }840{}^\circ )\] is

    A)  \[\frac{\sqrt{3}}{2}\]    

    B)                         \[-\frac{1}{2}\]  

    C)  \[\frac{1}{\sqrt{2}}\]                    

    D)         \[\frac{1}{2}\]

    Correct Answer: B

    Solution :

     \[\cos \,(-{{840}^{o}})=\cos (-{{36}^{o}}-{{36}^{o}}-{{12}^{o}})\] \[=\cos \,(-{{120}^{o}})\] \[=\cos {{120}^{o}}\] \[=-\frac{1}{2}\]


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