A) \[\left[ \begin{matrix} 0 & 0 \\ 0 & 0 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 1 & 0 \\ 0 & 0 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} 0 & 1 \\ 1 & 0 \\ \end{matrix} \right]\]
D) \[\left[ \begin{matrix} 1 & 0 \\ 0 & 1 \\ \end{matrix} \right]\]
Correct Answer: D
Solution :
\[\cos \theta \left[ \begin{matrix} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \\ \end{matrix} \right]+\sin \theta \left[ \begin{matrix} \sin \theta & -\cos \theta \\ \cos \theta & \sin \theta \\ \end{matrix} \right]\] =\[\left[ \begin{matrix} {{\cos }^{2}}\theta +{{\sin }^{2}}\theta & 0 \\ 0 & {{\cos }^{2}}\theta +{{\sin }^{2}}\theta \\ \end{matrix} \right]=\left[ \begin{matrix} 1 & 0 \\ 0 & 1 \\ \end{matrix} \right]\].
You need to login to perform this action.
You will be redirected in
3 sec
