A) \[\left[ \begin{matrix} -3 & 4 \\ 14 & -13 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 3 & -4 \\ -14 & 13 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} 3 & 4 \\ 14 & 13 \\ \end{matrix} \right]\]
D) \[\left[ \begin{matrix} -3 & 4 \\ -14 & 13 \\ \end{matrix} \right]\]
Correct Answer: A
Solution :
\[\left[ \begin{matrix} 3 & 1 \\ 4 & 1 \\ \end{matrix} \right]X=\left[ \begin{matrix} 5 & -1 \\ 2 & \,\,3 \\ \end{matrix} \right]\Rightarrow X=\left[ \begin{matrix} -3 & 4 \\ 14 & -13 \\ \end{matrix} \right]\] Since\[\left[ \begin{matrix} 3 & 1 \\ 4 & 1 \\ \end{matrix} \right]\,\,\left[ \begin{matrix} -3 & 4 \\ 14 & -\,13 \\ \end{matrix} \right]=\left[ \begin{matrix} 5 & -1 \\ 2 & 3 \\ \end{matrix} \right]\].
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