A) \[\left[ \begin{matrix} 1 & 3 \\ 2 & -1 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 1 & -3 \\ 2 & -1 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} 2 & 6 \\ 4 & -2 \\ \end{matrix} \right]\]
D) \[\left[ \begin{matrix} 2 & -6 \\ 4 & -2 \\ \end{matrix} \right]\]
Correct Answer: A
Solution :
\[2X\,=\left[ \begin{matrix} 3 & 8 \\ 7 & 2 \\ \end{matrix} \right]-\left[ \begin{matrix} 1 & 2 \\ 3 & 4 \\ \end{matrix} \right]\] \[2X=\left[ \begin{matrix} 2 & 6 \\ 4 & -2 \\ \end{matrix} \right]\Rightarrow X=\left[ \begin{matrix} 1 & 3 \\ 2 & -1 \\ \end{matrix} \right]\].
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