Answer:
Let AB be the height of a tree, as shown in Fig. and BC be its shadow cast by the sun. 
Let \[\angle ACB=\theta .\] Clearly, \[\tan \theta =\frac{AB}{BC}\] Take a rod A? B? and fix at such a point that the tip of its shadow coincides with the point C. Then \[\tan \theta =\frac{A'B'}{B'C}.\] Hence \[\frac{AB}{BC}=\frac{A'B'}{B'C}.\] \[\therefore \] Height of tree, \[AB=\frac{A'B'}{B'C}\times BC.\]
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