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JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Units

  • question_answer
    To determine the Young's modulus of a wire, the formula is \[Y=\frac{F}{A}:\frac{L}{\Delta L};\] where \[L\] = length, \[A=\]area of cross-section of the wire, \[\Delta L=\]change in length of the wire when stretched with a force \[F\]. The conversion factor to change it from CGS to MKS system is [MP PET 1983]

    A) 1

    B) 10

    C) 0.1

    D) 0.01

    Correct Answer: C

    Solution :

    \[Y=\frac{F}{A}.\frac{L}{\Delta L}\]= \[\frac{dyne}{c{{m}^{2}}}=\frac{{{10}^{-5}}N}{{{10}^{-4}}{{m}^{2}}}=0.1N/{{m}^{2}}\]


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