JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    Volume of \[\frac{N}{10}{{H}_{2}}S{{O}_{4}}\] required to neutralize 10 ml 5 N \[N{{a}_{2}}C{{O}_{3}}\] is

    A) 100 ml

    B) 50 ml

    C) 500 ml

    D) 1000 ml

    Correct Answer: C

    Solution :

    N1V1 = N2V2   \[\Rightarrow 5\times 10=\frac{1}{10x}\times x\,\,\,\,\therefore x=500ml\]


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