A) 1 gm
B) 4 gms
C) 40 gms
D) 10 gms
Correct Answer: A
Solution :
\[\text{Molarity}=\frac{wt.\times 1000}{\text{Eq}\text{. wt}\text{.}\times \text{vol}\text{.}}\] \[0.1=\frac{wt.\ \times \ 1000}{40\ \times \ 250}\] \ wt. required = 1 gm
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