A) 10 N
B) 1 N
C) 0.10 N
D) 100 N
Correct Answer: C
Solution :
\[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[{{N}_{1}}\times 20={{N}_{2}}\times 22.18\] \[{{N}_{1}}=\frac{{{N}_{2}}\times 22.18}{20}\] ???(i) \[NaOH\]solution = \[HCl\]solution \[{{N}_{2}}\times 21.5=\frac{1}{10}\times 20\] \[{{N}_{2}}=\frac{20}{10\times 21.5}\] ??.(ii) by eq. (i) and (ii) \[{{N}_{1}}=\frac{20\times 22.18}{20\times 10\times 21.5}=\frac{22.18}{215}=0.1N\]
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