A) \[63.64\]
B) \[\frac{63.64}{6.02\times {{10}^{23}}}\]
C) \[32.77\times 6.02\times {{10}^{23}}\]
D) \[63.64\times 6.02\times {{10}^{23}}\]
Correct Answer: B
Solution :
\[2\times 31.82\], \[\therefore \]wt of one atom \[=\frac{2\times 31.82}{N}=\frac{63.64}{N}\]
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