JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    10 ml of conc. \[{{H}_{2}}S{{O}_{4}}\] (18 molar) is diluted to 1 litre. The approximate strength of dilute acid could be [CPMT 1971]

    A) 0.18 N

    B) 0.36 N

    C) 0.09 N

    D) 18.00 N

    Correct Answer: B

    Solution :

    18 M of \[{{H}_{2}}S{{O}_{4}}\ =\ 36\ N\ \text{of}\ {{H}_{2}}S{{O}_{4}}\] \[{{N}_{1}}{{V}_{1}}\ =\ {{N}_{2}}{{V}_{2}}\]Þ 36 × 10 = N2 × 1000 \ N2 = 0.36 N


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