A) 2.76 g
B) 2.98 g
C) 2.16 g
D) 2.44 g
Correct Answer: C
Solution :
\[2A{{g}_{2}}C{{O}_{3}}\] \[\xrightarrow{\Delta }\] \[4Ag+2C{{O}_{2}}+{{O}_{2}}\] [(2 × 108) + 12 + 48] 4 × 108 2(216 + 12 + 48) 4 × 108 2 × 276 = 552 4 × 108 \[\because \] 552 gm silver carbonate gives silver = 432 gm. \ 2.76 gm silver carbonate gives \[\frac{432\times 2.76}{552}2.16gm\]
You need to login to perform this action.
You will be redirected in
3 sec
