question_answer

Define the terms magnifying power and solving power of a telescope.   

Answer:

                The magnifying power of a telescope in normal adjustment is defined as the ratio of the angle subtended by the image at the eye as seen through the telescope to the angle subtended by the object directly, hen both the object and the image lie at infinity. In normal adjustment, \[m=\frac{{{f}_{0}}}{{{f}_{e}}}\] When the final image is formed at the least distance of distinct vision, \[m=\frac{{{f}_{0}}}{{{f}_{e}}}\left( 1+\frac{{{f}_{e}}}{D} \right)\] The resolving power of a telescope is defined as the reciprocal of the smallest angular separation \[(d\theta )\] between two distant objects, whose images are just seen in the telescope as separate. \[R.P=\frac{1}{d\theta }=\frac{D}{1.22\lambda }\] where D is the diameter of the objective lens.