A) A deep red vapour is evolved
B) The vapour when passed into \[NaOh\] solution gives a yellow solution of \[N{{a}_{2}}Cr{{O}_{4}}\]
C) Chlorine gas is evolved
D) Chromyl chloride is formed
Correct Answer: A
Solution :
Chromyl chloride test \[4NaCl+{{K}_{2}}C{{r}_{2}}{{O}_{7}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow{\text{heat}}\]\[{{K}_{2}}S{{O}_{4}}+2N{{a}_{2}}S{{O}_{4}}+\underset{\text{chromyl chloride (orange }\,\text{red)}\,\,\,}{\mathop{2Cr{{O}_{2}}C{{l}_{2}}+3{{H}_{2}}O\,\,\,\,\,\,\,\,\,\,}}\,\] \[4NaOH+Cr{{O}_{2}}C{{l}_{2}}\to \underset{\,\,\,\,\,\,\,\text{Sod}\text{. chromate }\,\text{(Yellow)}}{\mathop{2NaCl\ +N{{a}_{2}}Cr{{O}_{4}}+2{{H}_{2}}O}}\,\] \[N{{a}_{2}}Cr{{O}_{4}}+\ {{(C{{H}_{3}}COO)}_{2}}Pb\to 2C{{H}_{3}}COONa+\]\[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\text{Lead chromate} \\ \,\,\,\,\,\,\,\,\text{(yellow ppt}\text{.)} \end{smallmatrix}}{\mathop{\,\,\,\,\,\,PbCr{{O}_{4}}\downarrow }}\,\]
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