A) The solution will remain colourless
B) The solution will become dark green
C) A yellow solution will be obtained
D) A yellow precipitate will be obtained
Correct Answer: D
Solution :
\[Cr{{O}_{2}}C{{l}_{2}}\ \xrightarrow{NaOH}\ N{{a}_{2}}Cr{{O}_{4}}\ \underset{C{{H}_{3}}COOPb}{\mathop{\xrightarrow{C{{H}_{3}}COOH}}}\,\] \[\left[ {{(C{{H}_{3}}COO)}_{2}}Pb \right]\ \xrightarrow{Cr{{O}_{2}}C{{l}_{2}}}\ \to \ \underset{\text{yellow ppt}\text{.}}{\mathop{PbCr{{O}_{4}}}}\,\]
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