A) Ferrous nitrite
B) \[FeS{{O}_{4}}NO\]
C) \[FeS{{O}_{4}}N{{O}_{2}}\]
D) Ferrous nitrate
Correct Answer: B
Solution :
When \[NO_{3}^{-}\]is passed through\[FeS{{O}_{4}}\] (neutral) and then few drops of conc. \[{{H}_{2}}S{{O}_{4}}\]is added then the brown ring is obtained. \[\underset{\begin{smallmatrix} \\ \end{smallmatrix}}{\mathop{FeS{{O}_{4}}\ +\ NO\ }}\,\underset{\text{Nitroso Ferrousulphate}}{\mathop{\underset{\text{(Brown}\ \text{ring)}}{\mathop{\to \,\,Fe(NO)S{{O}_{4}}\,\,\,}}\,}}\,\]
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