JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Wet Test for Acid Radical

  • question_answer
    A substance on treatment with dil \[{{H}_{2}}S{{O}_{4}}\] liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. The reaction indicates the presence of [IIT 1992]

    A) \[CO_{3}^{2-}\]

    B) \[{{S}^{2-}}\]

    C) \[SO_{3}^{2-}\]

    D) \[NO_{2}^{-}\]

    Correct Answer: C

    Solution :

    \[N{{a}_{2}}S{{O}_{3}}+2HCl(\text{dil}\text{.})\to 2NaCl+{{H}_{2}}O+S{{O}_{2}}\],   \[{{K}_{2}}C{{r}_{2}}{{O}_{2}}+{{H}_{2}}S{{O}_{4}}+3S{{O}_{4}}\to {{K}_{2}}S{{O}_{4}}+\underset{\text{(Green)}}{\mathop{C{{r}_{2}}{{(S{{O}_{4}})}_{3}}}}\,+{{H}_{2}}O\]


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