A) \[HCl\]
B) \[{{H}_{2}}S\] (alkaline)
C) \[{{(N{{H}_{4}})}_{2}}S\]
D) None of these
Correct Answer: B
Solution :
In presence of NH4OH, dissociation of H2S is remarkably high so increases the solubility product of IVth group sulphides \[{{H}_{2}}S\]\[2{{H}^{+}}+{{S}^{2-}}\] \[N{{H}_{4}}OH\to NH_{4}^{+}+O{{H}^{-}}\] \[O{{H}^{-}}\ +\ {{H}^{+}}\ \to \ {{H}_{2}}O\]
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