A) \[N{{m}^{2}}\]
B) \[kg\,m/{{s}^{2}}\]
C) \[1Nm\]
D) \[{{N}^{2}}{{m}^{2}}\]
Correct Answer: C
Solution :
\[\text{1joule}=\text{1Newton}\times \text{1meter}\]
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