A) more than object B
B) less than object B
C) Same as B
D) Cannot say
Correct Answer: A
Solution :
\[W=F.d\] For object A \[{{W}_{A}}=8\times {{d}_{A}}\] For object B \[{{W}_{B}}=16\times {{d}_{B}}\] Since, \[{{W}_{A}}={{W}_{B}}\] \[\therefore \] \[8\times {{d}_{A}}=16\times {{d}_{B}}\] \[\Rightarrow \]\[{{d}_{A}}=\frac{16}{8}\times {{d}_{B}}\] \[\therefore \] \[{{d}_{A}}=2{{d}_{B}}\] \[i.e.\]
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