A) \[\frac{2\pi M}{K}\]
B) \[\frac{K}{Mx}\,\frac{\sqrt{K}}{M}\]
C) \[\frac{\sqrt{K}}{M}\]
D) \[\frac{\sqrt{K}}{Mx}\]
Correct Answer: B
Solution :
Elastic potential energy stored in the spring in stretching it through a distance\[x=\frac{1}{2}K{{x}^{2}}\]. The velocity of the mass attached to the spring becomes maximum when the entire elastic potential energy gets converted into kinetic energy. So, \[\frac{1}{2}K{{x}^{2}}=\frac{1}{2}M{{v}^{2}}\] or \[v=\sqrt{\frac{K}{M}}x\]
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