question_answer

  Given linear equations are    

	A	B	C
x	½	0	1
Y	0	-1	1

Plot the points and  to get the line  

	D	E	F
x	5	3	1
y	4	5	6

Plot the points and  to get the line  (i) Clearly two lines intersect at point (3, 5) x = 3 and y = 5 is the solution (ii) Draw EL as perpendicular on Y-axis. Let intersecting point of lines x + 2y = 13 with Y = axis be M. the coordinates of point M are  Area of required triangle sq. units

Answer:

  Draw the graphs of following equations : 2x - y = 1, x + 2y = 13 (i) Find the solution of the equations from the graph. (ii) Shade the triangular region formed by the lines and the y-axis.