Answer:
From right triangles and we get
and
...(1)
Similarly, we have
?(2)
and ?(3)
Adding (1), (2) and (3), we get
(OB2 - OC2) + (OC2 - OA2)
+ (OA2 - OB2) = (BD2 - CD2) + (CE2
- AE2) + (AF2 - BF2)
0
= (BD2 + CE2 + AF2) - (AE2 + CD2
+ BF2)
AF2
+ BD2 + CE2 = AE2 + BF2 + CD2
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