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NEET AIPMT SOLVED PAPER MAINS 2010

  • question_answer
    The decay constant of a radio isotope is \[\lambda .\] If\[{{A}_{1}}\]and \[{{A}_{2}}\] are its activities at times \[{{t}_{1}}\] and \[{{t}_{2}}\] respectively, the number of nuclei which have decayed during the time \[({{t}_{1}}-{{t}_{2}})\]                         

    A)  \[{{A}_{1}}{{t}_{1}}-{{A}_{2}}{{t}_{2}}\]

    B)  \[{{A}_{1}}-{{A}_{2}}\] 

    C)  \[\frac{({{A}_{1}}-{{A}_{2}})}{\lambda }\]           

    D)  \[\lambda ({{A}_{1}}-{{A}_{2}})\]

    Correct Answer: C

    Solution :

    \[{{A}_{1}}=\lambda {{N}_{1}}\] \[{{A}_{2}}=\lambda {{N}_{2}}\] \[{{N}_{1}}-{{N}_{2}}=\left[ \frac{{{A}_{1}}-{{A}_{2}}}{\lambda } \right]\]


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