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NEET AIPMT SOLVED PAPER MAINS 2010

  • question_answer
    A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity \[\omega .\]Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by             

    A) \[\frac{(M+2m)\omega }{2m}\]

    B) \[\frac{(M+2m)\omega }{2m}\]

    C) \[\frac{(M+2m)\omega }{M}\] 

    D) \[\frac{M\omega }{M+2m}\]

    Correct Answer: D

    Solution :

    In the absence of external torque, angular momentum remain constant \[L=I\omega =I'\omega '\]                 \[\therefore \]  \[M{{R}^{2}}\omega =(M+2m){{R}^{2}}\omega '\]                                 \[\omega '=\frac{M\omega }{(M+2m)}\]


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