A) 2-iodopro'pane
B) allyl iodide
C) propene
D) glycerol triiodide
Correct Answer: A
Solution :
\[\underset{\begin{align} & \text{ }\!\!|\!\!\text{ } \\ & \text{CHOH} \\ & \text{ }\!\!|\!\!\text{ } \\ & \text{C}{{\text{H}}_{\text{2}}}\text{OH} \\ \end{align}}{\mathop{\text{C}{{\text{H}}_{\text{2}}}\text{OH}}}\,\underset{\text{(highly}\,\text{unstable)}}{\mathop{\xrightarrow[\text{-3}{{\text{H}}_{\text{2}}}\text{O}]{\text{3HI}}\underset{\begin{align} & \text{ }\!\!|\!\!\text{ } \\ & \text{CHI} \\ & \text{ }\!\!|\!\!\text{ } \\ & \text{C}{{\text{H}}_{\text{2}}}\text{I} \\ \end{align}}{\mathop{\text{C}{{\text{H}}_{\text{2}}}\text{I}}}\,\xrightarrow[-{{\text{I}}_{\text{2}}}]{{}}}}\,\underset{\text{allyl}\,\text{iodide}}{\mathop{\underset{\begin{align} & \text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ } \\ & \text{CH} \\ & \text{ }\!\!|\!\!\text{ } \\ & \text{C}{{\text{H}}_{\text{2}}}\text{I} \\ \end{align}}{\mathop{\text{C}{{\text{H}}_{\text{2}}}}}\,}}\,\] \[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{(}\,\text{unstable)}}{\mathop{\xrightarrow[{}]{\text{HI}\,\,\text{(excess)}}\underset{\begin{align} & \text{ }\!\!|\!\!\text{ } \\ & \text{CHI} \\ & \text{ }\!\!|\!\!\text{ } \\ & \text{C}{{\text{H}}_{\text{2}}}\text{I} \\ \end{align}}{\mathop{\text{C}{{\text{H}}_{3}}}}\,\xrightarrow[-{{\text{I}}_{\text{2}}}]{{}}}}\,\underset{{}}{\mathop{\underset{\begin{align} & \text{ }\!\!|\!\!\text{ } \\ & \text{CH} \\ & \text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ } \\ & \text{C}{{\text{H}}_{\text{2}}} \\ \end{align}}{\mathop{\text{C}{{\text{H}}_{3}}}}\,}}\,\] \[\xrightarrow[{}]{\text{HI}}\underset{\text{2-iodopropane}}{\mathop{\underset{\begin{align} & \text{ }\!\!|\!\!\text{ } \\ & \text{CHI} \\ & \text{ }\!\!|\!\!\text{ } \\ & \text{C}{{\text{H}}_{\text{2}}} \\ \end{align}}{\mathop{\text{C}{{\text{H}}_{3}}}}\,}}\,\]
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