A) Pure sodium metal dissolves in liquid ammonia to give blue solution
B) NaOH reacts with glass to give sodium silicate
C) Aluminium, reacts with excess NaOH to give \[Al{{(OH)}_{3}}\]
D) \[NaHC{{O}_{3}}\] on heating gives\[N{{a}_{2}}C{{O}_{3}}\]
Correct Answer: C
Solution :
Aluminium being amphoteric reacts with aqueous alkalies with the evolution of H2 gas. \[2Al(s)+2NaOH(aq)+6{{H}_{2}}O(l)\] \[\xrightarrow[{}]{{}}2N{{a}^{+}}{{[Al{{(OH)}_{4}}]}^{-}}(aq)+3{{H}_{2}}(g)\uparrow \] sodium tetrahydroxoaluminate (III)
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