A) n = 6 to n = 1
B) n = 5 to n = 4
C) n = 6 to n = 5
D) n = 5 ton = 3
Correct Answer: C
Solution :
\[\because \Delta E\propto \left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right],\]where \[{{n}_{2}}>{{n}_{1}}\]Energy of photon obtained from the transition n = 6 to n = 5 will have least energy.
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