A) \[\text{O}_{2}^{-},\text{O}_{2}^{2-}\]Both diamagnetic
B) \[{{O}^{+}},\,O_{2}^{2-}-\] Both paramagnetic
C) \[O_{2}^{+},\,{{O}_{2}}-\] Both paramagnetic
D) \[\text{O}_{{}}^{{}},\text{O}_{2}^{2-}\]- Both paramagnetic
Correct Answer: B
Solution :
The molecular orbital configurations of \[O_{2}^{+},O_{2}^{-},O_{2}^{2-}\]and\[{{O}_{2}}\] are \[O_{2}^{+}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\overset{{}}{\mathop{\sigma }}\,2s_{z}^{2},\pi 2p_{x}^{2}\approx \pi 2p_{y}^{2},\]\[\overset{*}{\mathop{\pi }}\,2p_{x}^{1}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{2}\] \[O_{2}^{-}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\pi 2p_{x}^{2}\] \[\approx \pi 2p_{y,}^{2}\overset{*}{\mathop{\pi }}\,2p_{x}^{2}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{1}\] \[O_{2}^{2}-=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2s_{z}^{2},\pi 2p_{x}^{2}\] \[\approx \pi 2p_{y,}^{2}\overset{*}{\mathop{\pi }}\,2p_{x}^{2}\approx \overset{*}{\mathop{\pi }}\,2p_{y.}^{2}\] \[{{O}_{2}}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\pi 2p_{x}^{2}\] \[\approx \pi 2p_{y,}^{2}\overset{*}{\mathop{\pi }}\,2p_{x}^{1}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{1}\] And the electronic configuration of O and \[{{O}^{+}}\]are \[O=1{{s}^{2}},2{{s}^{2}},2p_{x,}^{2}2p_{y,}^{1}2p_{z}^{1}\] \[{{O}^{+}}=1{{s}^{2}},\,2{{s}^{2}},\,2p_{x}^{1},\,2p_{y}^{1},\,2p_{z}^{1}\] As\[O_{2}^{+},{{O}_{2}},O_{2,}^{-}O\]and \[{{O}^{+}}\]have unpaired electrons, hence are paramagnetic.
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