NEET AIPMT SOLVED PAPER MAINS 2012

  • question_answer
    The dimensions of \[{{({{\mu }_{0}}{{\varepsilon }_{0}})}^{-1/2}}\] are                  

    A) \[[{{L}^{1/2}}T{{-}^{1/2}}]\]        

    B) \[[{{L}^{-1}}T]\]

    C) \[[L{{T}^{-1}}]\]

    D) \[[{{L}^{1/2}}{{T}^{1/2}}]\]

    Correct Answer: C

    Solution :

    \[{{({{\mu }_{0}}{{\varepsilon }_{0}})}^{-1/2}}\]is velocity of light Hence \[c=\frac{1}{\sqrt{({{\mu }_{0}}{{\varepsilon }_{0}})}}=[L{{T}^{-1}}]\]


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