A) \[\sqrt{{{\mu }_{s}}mRg}\]
B) \[\sqrt{Rg/{{\mu }_{s}}}\]
C) \[\sqrt{m\,Rg/{{\mu }_{s}}}\]
D) \[\sqrt{{{\mu }_{s}}Rg}\]
Correct Answer: D
Solution :
In this condition, centripetal force is equal to static frictional force between road and tyres, So \[{{\mu }_{s}}mg=\frac{m{{v}^{2}}}{R}\] \[{{v}_{\max }}=\sqrt{{{\mu }_{s}}Rg}\]
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