NEET AIPMT SOLVED PAPER MAINS 2012

  • question_answer
    The equation of a simple harmonic wave is given by\[y=3\sin \frac{\pi }{2}(50t-x),\]where x and y are in metres and t is in seconds. The ratio of maximum particle velocity to the wave velocity is

    A)  \[2\pi \]                              

    B) \[\frac{3}{2}\pi \]                            

    C)  \[3\pi \]                              

    D) \[\frac{2}{3}\pi \]

    Correct Answer: B

    Solution :

    We know that \[{{v}_{\max }}=a\omega \] and        \[v=n\lambda \] \[\therefore \]  \[\frac{{{v}_{\max }}}{v}=\frac{a\omega }{n\lambda }\]                 \[=\frac{a(2\pi n)}{n\pi }=\frac{2\pi a}{\lambda }\]                 \[=\frac{2\pi a}{2\pi /k}\]                 \[=ka=\frac{\pi }{2}\times 3\]                 \[=\frac{3\pi }{2}\]         


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