NEET AIPMT SOLVED PAPER MAINS 2012

  • question_answer
    A parallel plate capacitor has a uniform electric field E in the space between the plates. If the distance between the plates is d and area of each plate is A, the energy stored in the capacitor is

    A) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}\]          

    B) \[{{E}^{2}}Ad/{{\varepsilon }_{0}}\]        

    C) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}Ad\]     

    D) \[{{\varepsilon }_{0}}EAd\]

    Correct Answer: C

    Solution :

    Energy density for a parallel plate capacitor \[=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}\]and volume = Ad Total energy = energy density x volume                                 \[=\left( \frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}} \right)\times (Ad)\]                                 \[=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}Ad\]


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