A) \[20\,\Omega \]
B) \[15\,\Omega \]
C) \[10\,\Omega \]
D) \[30\,\Omega \]
Correct Answer: C
Solution :
Here, \[{{R}_{1}}=R=?\] \[{{R}_{2}}=5\Omega ,V=10\,V\] And \[p=30\,W\] Hence \[p=\frac{{{V}_{2}}}{{{R}_{1}}}+\frac{{{V}_{2}}}{{{R}_{2}}}\] \[\frac{{{10}^{2}}}{R}=30-\frac{{{10}^{2}}}{5}\] \[\frac{100}{R}=30-20\]
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