A) 2.5
B) 5.0
C) 7.5
D) 10.0
Correct Answer: C
Solution :
: Let\[{{I}_{1}}=\]current along path\[(1-2-3-4-5)\] \[\therefore \]\[{{I}_{1}}\times 4R=\]10 volt ... (i) \[{{V}_{2-5}}={{I}_{1}}\times {{R}_{2-5}}={{I}_{1}}\times 3R\] \[=\frac{10}{4R}\times 3R\] form (i) \[=\frac{30}{4}=7.5\text{ }volt.\]
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