question_answer

A capactior of\[3\mu F\]capacity can be formed by connecting three\[2\mu F\]capacitors as in

A)  

B)  

C)  

D)  

Correct Answer: A

Solution :

: The two capacitors are in series \[\therefore \]\[{{C}_{s}}=\frac{2\times 2}{(2+2)}=\frac{4}{4}=1\mu F\] \[{{C}_{s}}\]and one capacitor are in parallel \[\therefore \] \[C={{C}_{s}}+2\mu F\] Or \[C=1\mu F+2\mu F\] Or \[C=3\mu F\]