A) \[1/11\]
B) \[2/11\]
C) \[3/11\]
D) \[4/11\]
Correct Answer: B
Solution :
: Volume of iceberg = V Density of iceberg\[=0.9\text{ }g/cc\] \[\therefore \] Mass of iceberg\[=V\times 0.9\] gram Let the volume above water level in sea\[=v\] \[\therefore \] Volume of iceberg immersed\[=(V-v)\] \[\therefore \] Volume ofseawater displaced\[=(V-v)\] \[\therefore \] ass of seawater displaced \[=(V-v)1.1\] Since Weight of floating body = Weight of sea water displaced \[\therefore \]\[V\times 0.9\times g=(V-v)\times 1.1\times g\] or \[0.9V=1.1V-1.1v\]or\[1.1v=1.1V-0.9V\] or \[\frac{v}{V}=\frac{0.2}{1.1}=\frac{2}{11}\]
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