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AMU Medical AMU Solved Paper-1996

  • question_answer
    The angular speed of earth in rad/s so that the objects on equator may appear weightless (taking\[g=10\text{ }m/{{s}^{2}}\]and radius of earth\[=6400\] km) is

    A)  \[1.56\]

    B)  \[1.25\times {{10}^{-1}}\]

    C)  \[1.56\times {{10}^{-3}}\]

    D)  \[1.25\times {{10}^{-3}}\]

    Correct Answer: D

    Solution :

    : Weight of the body = Centripetal force \[\therefore \]\[mg=mR{{\omega }^{2}}\] or\[\omega =\sqrt{g/R}=\sqrt{\frac{10}{6400\times {{10}^{3}}}}=\frac{1}{8\times {{10}^{2}}}\] \[=1.25\times {{10}^{-3}}rad/\sec \]


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