A) \[C{{H}_{4}}\]
B) \[N{{H}_{3}}\]
C) \[{{H}_{2}}O\]
D) \[P{{H}_{3}}\]
Correct Answer: D
Solution :
: \[C{{H}_{4}}=109{}^\circ \text{ }28,\text{ }N{{H}_{3}}=106{}^\circ 45\] \[{{H}_{2}}O=104{}^\circ 35,\text{ }P{{H}_{3}}=93{}^\circ 20\]
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