question_answer

The number of possible isomeric compounds for molecular formula \[{{C}_{5}}{{H}_{10}}\]would be

A)  8               

B)  7

C)  6               

D)  5

Correct Answer: B

Solution :

: Isomers of\[{{C}_{5}}{{H}_{10}}\]is 7: \[\underset{1-pentene}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-CH=C{{H}_{2}}}}\,\] \[\underset{2-methylbutene}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{3}}}}\,\]\[\underset{3-methyl-1-butene}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-HC=C{{H}_{2}}}}\,\] \[\underset{2-methyl-2-butene}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,-CH=C{{H}_{3}}}}\,,\] \[\underset{\begin{smallmatrix}  \,\,\,\,\,\,2-pentene \\  (c\text{ }is\text{ }and\text{ }trans) \end{smallmatrix}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-CH=HC-C{{H}_{3}}}}\,\]