AMU Medical AMU Solved Paper-1997

  • question_answer
    If\[{{\varepsilon }_{0}}\]and\[{{\mu }_{0}}\]are respectively, the electric permittivity and magnetic permeability of free space,\[\varepsilon \]and\[\mu \]are the corresponding quantities in a medium the refractive index of the medium is

    A)  \[\sqrt{\frac{\mu \varepsilon }{{{\mu }_{0}}{{\varepsilon }_{0}}}}\]

    B)  \[\sqrt{\frac{{{\mu }_{0}}{{\varepsilon }_{0}}}{{{\varepsilon }_{0}}}}\]

    C)  \[\frac{\mu \varepsilon }{{{\mu }_{0}}{{\varepsilon }_{0}}}\]

    D)  \[{{\left( \frac{\mu \varepsilon }{{{\mu }_{0}}{{\varepsilon }_{0}}} \right)}^{2}}\]

    Correct Answer: A

    Solution :

    : Refractive index of medium \[=\frac{Velocity\text{ }in\text{ }vacuum}{Velocity\text{ }in\text{ }medium}\] \[\therefore \] \[\mu =\frac{1/\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}{1/\sqrt{\mu \varepsilon }}\] or \[\mu =\sqrt{\frac{\mu \varepsilon }{{{\mu }_{0}}{{\varepsilon }_{0}}}}\]


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