A) \[N{{H}_{3}}>{{H}_{2}}O>{{H}_{2}}S\]
B) \[{{H}_{2}}S>N{{H}_{3}}>{{H}_{2}}O\]
C) \[{{H}_{2}}S>{{H}_{2}}O>N{{H}_{3}}\]
D) \[{{H}_{2}}O>N{{H}_{3}}>{{H}_{2}}S\]
Correct Answer: A
Solution :
: For\[N{{H}_{3}}\]bond angle\[(H\overset{\wedge }{\mathop{N}}\,H)\]is\[107{}^\circ \]. For\[{{H}_{2}}O\]bond angle\[(H\overset{\wedge }{\mathop{O}}\,H)\]is\[104.5{}^\circ \]. For\[{{H}_{2}}S\]bond angle\[(H\overset{\wedge }{\mathop{S}}\,H)\]is\[92{}^\circ \].
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