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AMU Medical AMU Solved Paper-1997

  • question_answer
    In the reaction\[_{1}^{2}H+_{1}^{2}H\to _{2}^{4}He,5.5\times {{10}^{8}}\]K cal/mole of energy is produced. Calculate the energy per gram of He

    A) \[5.50\times {{10}^{8}}K.cal\]  

    B)  \[1.10\times {{10}^{8}}K.cal\]

    C)  \[2.75\times {{10}^{8}}K.cal\]  

    D)  \[1.37\times {{10}^{8}}K.cal\]

    Correct Answer: D

    Solution :

    : Molar mass of \[He=4\] Energy per gram of \[He=\frac{5.5\times {{10}^{8}}}{4}\] \[=1.37\times {{10}^{8}}Kcal\]


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