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AMU Medical AMU Solved Paper-1998

  • question_answer
    A beaker of radius 6 cm is filled with mercury up to a height to 12 cm. Given that the density of mercury is\[13600\text{ }kg/{{m}^{3}},\]the force exerted by the mercury on the bottom of the beaker is approximately.

    A)  184 N           

    B)  1100N

    C)  1200 N          

    D)  1300 N

    Correct Answer: A

    Solution :

    : Pressure of mercury on bottom\[=dgh\] \[P=13600\times 10\times \frac{12}{100}N{{m}^{-2}}\] Area of bottom\[=\pi {{R}^{2}}=3.14\times {{\left( \frac{6}{100} \right)}^{2}}{{m}^{2}}\] \[\therefore \]Force = Pressure\[\times \]area or Force\[=\frac{13600\times 10\times 12\times 3.14\times 36}{100\times 100\times 100}N\] or Force = 184.48 N.


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