A) halved
B) doubled
C) unchanged
D) quadrupled
Correct Answer: B
Solution :
: \[{{\beta }_{1}}=\frac{D\lambda }{d}{{\beta }_{2}}=\frac{D\lambda \times 2}{d}\] \[\therefore \] \[{{\beta }_{2}}=2{{\beta }_{1}}\]
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