A) 6.25 A
B) 5.25 A
C) 5.75 A
D) 8.13 A
Correct Answer: C
Solution :
: At resonance\[{{X}_{L}}={{X}_{C}}\] \[\therefore \]\[I=\frac{E}{\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}}\] Or \[I=\frac{E}{R}=\frac{230}{40}=5.75A\]
You need to login to perform this action.
You will be redirected in
3 sec
