A) 0, 3.14, 6.28
B) 0, 1.57, 4.71
C) 1.57, 4.71, 7.85
D) none of the above
Correct Answer: D
Solution :
: When resistance R is negligible, \[n=\frac{1}{2\pi \sqrt{LC}}\] \[\therefore \] \[n=\frac{1}{2\pi \sqrt{40\times {{10}^{-3}}\times 25\times {{10}^{-6}}}}\] \[\therefore \] \[n=\frac{{{10}^{3}}}{2\pi }\] \[\therefore \] \[T=\frac{1}{n}=\frac{2\pi }{{{10}^{3}}}\sec =2\pi \]milli sec As energy is magnetic at times \[t=\frac{T}{2},T,\frac{3T}{2}....\] Hence \[t=\pi ,2\pi ,3\pi ..........\]milli sec \[=3.14,6.28,9.42\]milli sec.
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