A) \[150\text{ }oh{{m}^{-1}}c{{m}^{-1}}mo{{l}^{-1}}\]
B) \[\text{75 }oh{{m}^{-1}}c{{m}^{-1}}mo{{l}^{-1}}\]
C) \[\text{80 }oh{{m}^{-1}}c{{m}^{-1}}mo{{l}^{-1}}\]
D) all of the above
Correct Answer: C
Solution :
: Molar conductivity, \[{{\wedge }_{m}}=160\,oh{{m}^{-1}}c{{m}^{2}}/mol\] \[{{\wedge }_{m}}=\frac{k\times 1000}{Molarity}\] \[{{\wedge }_{eq}}=\frac{k\times 1000}{Normality}\] \[\frac{{{\wedge }_{eq}}}{{{\wedge }_{m}}}=\frac{Molarity}{Normality}\] \[{{\wedge }_{eq}}=\frac{{{\wedge }_{m}}\times number\text{ }of\text{ }moles\text{ }per\text{ }litre}{number\text{ }of\text{ }gm\text{ }equivalents\text{ }per\text{ }litre}\] \[{{\wedge }_{eq}}=\frac{160\times eq.\,wt}{mol.wt.}\] \[=\frac{160\times mol.\,wt.}{2\times mol.wt}\] \[=80\text{ }oh{{m}^{-1}}c{{m}^{2}}e{{q}^{-1}}\].
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