A) 1-propanol
B) methanol
C) 2-butanol
D) 1-butanol
Correct Answer: C
Solution :
Key Idea: It is used to detect presence of \[C{{H}_{3}}-\overset{\text{O}}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\] group and \[C{{H}_{3}}-\overset{OH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}\,-H\] group. The compounds having these groups give yellow ppt. of iodoform when \[{{I}_{2}}\]and aq. \[\text{NaOH}\]is added. (a)\[\underset{1-\text{propanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH}}\,\] (b) \[\underset{\text{methanol}}{\mathop{\text{C}{{\text{H}}_{\text{3}}}\text{OH}}}\,\] (c) \[\underset{2-\text{butanol}}{\mathop{C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,HC{{H}_{2}}C{{H}_{3}}}}\,\] (d) \[\underset{1-\text{butanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}OH}}\,\] \[\therefore \] Only 2-butanol gives iodoform test.
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