A) primary alcohol
B) secondary alcohol
C) tertiary alcohol
D) all of the above
Correct Answer: C
Solution :
Key Idea: \[Aldehyde\xrightarrow{\text{Reduction}}{{1}^{o}}alcohol\] \[Ketone\xrightarrow[{}]{\text{Reduction}}{{2}^{o}}alcohol\] \[\therefore \]Carbonyl compounds (aldehydes and ketones) give \[{{1}^{o}}\] and \[{{2}^{o}}\] alcohol on reduction. \[\therefore \]\[{{3}^{o}}\]alcohol are not formed by reduction of carbonyl compounds.
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